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Why Zig when there is already C++, D, and Rust?

If Zig code doesn’t look like it’s jumping away to call a function, then it isn’t. This means you can be sure that the following code calls only foo() and then bar() , and this is guaranteed without needing to know the types of anything:
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Software EngineeringProgramming Languages2021

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SubmittedTitle on HNPointsComments
Jan 15, 2021Why Zig when there is already C++, D, and Rust? by mardiyah276259
Jan 22, 2024Why Zig When There Is Already C++, D, and Rust? by whitepoplar155204

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